What is the derivative of (4x^{2/3}/(x^2+1)) ?

The derivative of (4x^{2/3}/(x^2+1)) is (4(-4x^2+2))/(3x^{1/3)(x^2+1)^2}

What is the first derivative of (4x^{2/3}/(x^2+1)) ?

The first derivative of (4x^{2/3}/(x^2+1)) is (4(-4x^2+2))/(3x^{1/3)(x^2+1)^2}

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\frac{d}{d x} (\frac{4 x ^{\frac{2}{3}}}{x ^{2} + 1})

\frac{4 ( - 4 x ^{2} + 2 )}{3 x ^{\frac{1}{3}} ( x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x ^{\frac{2}{3}}}{x ^{2} + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x ^{\frac{2}{3}}}{x ^{2} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d}{d x} ( x ^{\frac{2}{3}} ) ( x ^{2} + 1 ) - \frac{d}{d x} ( x ^{2} + 1 ) x ^{\frac{2}{3}}}{( x ^{2} + 1 ) ^{2}}

\frac{d}{d x} (x^{\frac{2}{3}}) = \frac{2}{3 x ^{\frac{1}{3}}}

\frac{d}{d x} (x^{2} + 1) = 2 x

= 4 \cdot \frac{\frac{2}{3 x ^{\frac{1}{3}}} ( x ^{2} + 1 ) - 2 x x ^{\frac{2}{3}}}{( x ^{2} + 1 ) ^{2}}

Simplify

4 \cdot \frac{\frac{2}{3 x ^{\frac{1}{3}}} ( x ^{2} + 1 ) - 2 x x ^{\frac{2}{3}}}{( x ^{2} + 1 ) ^{2}} : \frac{4 ( - 4 x ^{2} + 2 )}{3 x ^{\frac{1}{3}} ( x ^{2} + 1 ) ^{2}}

= \frac{4 ( - 4 x ^{2} + 2 )}{3 x ^{\frac{1}{3}} ( x ^{2} + 1 ) ^{2}}

\int \frac{1}{( x + 1 ) x ^{2} + 2 x - 15} d x

x \to 3 + lim (\frac{2}{x ^{2} - 9})

\frac{e ^{x}}{5 x ^{6}}

x \to - 3 lim (2 x^{2} + 3 x)

\int \frac{1}{a t + b} d t

What is the derivative of (4x^{2/3}/(x^2+1)) ?
The derivative of (4x^{2/3}/(x^2+1)) is (4(-4x^2+2))/(3x^{1/3)(x^2+1)^2}
What is the first derivative of (4x^{2/3}/(x^2+1)) ?
The first derivative of (4x^{2/3}/(x^2+1)) is (4(-4x^2+2))/(3x^{1/3)(x^2+1)^2}