What is the slope ofintercept (1,-1),(-1,-2) ?

The slope ofintercept (1,-1),(-1,-2) is y= 1/2 x-3/2

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slope ofintercept (1,-1),(-1,-2)

slope intercept

(1, - 1), (- 1, - 2)

y = \frac{1}{2} x - \frac{3}{2}

Solution steps

Compute the slope

(1, - 1), (- 1, - 2) : m = \frac{1}{2}

Compute the

y

intercept:

b = - \frac{3}{2}

Construct the line equation

y = mx + b

where

m = \frac{1}{2}

and

b = - \frac{3}{2}

y = \frac{1}{2} x - \frac{3}{2}

\int_{0}^{1} x e^{- x^{2}} d x

\int - \frac{1}{1 + x ^{2}} d x

\int sin (- 1 (x)) d x

x \to 0 - lim (\frac{sec ( x )}{x})

y^{^{''}} + 6 y^{^{'}} + 6 y = 0, y (0) = 1, y^{^{'}} (0) = 2

What is the slope ofintercept (1,-1),(-1,-2) ?
The slope ofintercept (1,-1),(-1,-2) is y= 1/2 x-3/2