What is the limit as x approaches 3-of (x+3)/(x^2-9) ?

The limit as x approaches 3-of (x+3)/(x^2-9) is -infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 3-of (x+3)/(x^2-9)

x \to 3 - lim (\frac{x + 3}{x ^{2} - 9})

- \infty

Solution steps

x \to 3 - lim (\frac{x + 3}{x ^{2} - 9})

Simplify

\frac{x + 3}{x ^{2} - 9} : \frac{1}{x - 3}

= x \to 3 - lim (\frac{1}{x - 3})

For

x

approaching

3

from the left

, x < 3 \Rightarrow x - 3 < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

\int \frac{4}{e ^{t}} d t

\int \frac{1}{4 sin ( x ) + 3 cos ( x )} d x

ln (6 - 7 x)

\frac{d}{d x} (e^{- x^{2} - y^{2}} cos (x y))

x \to - 5 lim (3 x^{3} + 15 x^{2} - 25)

What is the limit as x approaches 3-of (x+3)/(x^2-9) ?
The limit as x approaches 3-of (x+3)/(x^2-9) is -infinity