What is the sum from n=1 to infinity of n^2e^{-n^3} ?

The sum from n=1 to infinity of n^2e^{-n^3} is converges

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sum from n=1 to infinity of n^2e^{-n^3}

n = 1 \sum \infty n^{2} e^{- n^{3}}

converges

Solution steps

n = 1 \sum \infty n^{2} e^{- n^{3}}

Apply Series Ratio Test:

converges

= converges

\frac{6}{s ^{2} + 9}

x \to 3 - lim (\frac{2}{( x - 3 )})

\frac{\partial}{\partial u ( v )} (\frac{e ^{v}}{u ( v ) + v ^{9}})

0.3 x^{3} 5^{x}

What is the sum from n=1 to infinity of n^2e^{-n^3} ?
The sum from n=1 to infinity of n^2e^{-n^3} is converges