What is the integral of sec^2(2y) ?

The integral of sec^2(2y) is 1/2 tan(2y)+C

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integral of sec^2(2y)

\int sec^{2} (2 y) d y

\frac{1}{2} tan (2 y) + C

Solution steps

\int sec^{2} (2 y) d y

Apply u-substitution

: \int sec^{2} (u) \frac{1}{2} d u

= \int sec^{2} (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= \frac{1}{2} tan (u)

Substitute back

u = 2 y

= \frac{1}{2} tan (2 y)

Add a constant to the solution

= \frac{1}{2} tan (2 y) + C

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