What is the integral from-2 to 2 of 2-sqrt(4-x^2) ?

The integral from-2 to 2 of 2-sqrt(4-x^2) is 8-2pi

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integral from-2 to 2 of 2-sqrt(4-x^2)

\int_{- 2}^{2} 2 - 4 - x^{2} d x

8 - 2 π

Decimal Notation

1.71681 \dots

Solution steps

\int_{- 2}^{2} 2 - 4 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} 2 d x - \int_{- 2}^{2} 4 - x^{2} d x

\int_{- 2}^{2} 2 d x = 8

\int_{- 2}^{2} 4 - x^{2} d x = 2 π

= 8 - 2 π

\frac{1}{s + 5}

f (x) = - 5 x^{2}, at x = 8

x (x + 1) (\frac{d y}{d x}) + x y = 1, y (e) = 1

\int \frac{1}{9 x - 7} d x

y = y^{^{'}}

What is the integral from-2 to 2 of 2-sqrt(4-x^2) ?
The integral from-2 to 2 of 2-sqrt(4-x^2) is 8-2pi