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Popular >

d/(dy)(e^{-1/(y^3)})

Solution

\frac{d}{d y} (e^{- \frac{1}{y ^{3}}})

Solution

\frac{3 e ^{- \frac{1}{y ^{3}}}}{y ^{4}}

Solution steps

\frac{d}{d y} (e^{- \frac{1}{y ^{3}}})

Apply the chain rule:

e^{- \frac{1}{y ^{3}}} \frac{d}{d y} (- \frac{1}{y ^{3}})

= e^{- \frac{1}{y ^{3}}} \frac{d}{d y} (- \frac{1}{y ^{3}})

\frac{d}{d y} (- \frac{1}{y ^{3}}) = \frac{3}{y ^{4}}

= e^{- \frac{1}{y ^{3}}} \frac{3}{y ^{4}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 e ^{- \frac{1}{y ^{3}}}}{y ^{4}}

Popular Examples

derivative of ((x(x-1)/(2x^2(x+1)))^3)

\frac{d}{d x} ((\frac{x ( x - 1 )}{2 x ^{2} ( x + 1 )})^{3})

derivative of 11sqrt(x)derivative of

11 x

y^{''}-y^'-12y=e^{4x}

y^{^{''}} - y^{^{'}} - 12 y = e^{4 x}

integral of (sin(x)tan(x))/1

\int \frac{sin ( x ) tan ( x )}{1} d x

integral from 0 to 4 of 1/(sqrt(16-x^2))

\int_{0}^{4} \frac{1}{16 - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the d/(dy)(e^{-1/(y^3)}) ?
The d/(dy)(e^{-1/(y^3)}) is (3e^{-1/(y^3)})/(y^4)
What is the first d/(dy)(e^{-1/(y^3)}) ?
The first d/(dy)(e^{-1/(y^3)}) is (3e^{-1/(y^3)})/(y^4)