What is the solution for dy+(3x^2y-x^2)dx=0 ?

The solution for dy+(3x^2y-x^2)dx=0 is y=(e^{-x^3+c_{1}})/3+1/3

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dy+(3x^2y-x^2)dx=0

d y + (3 x^{2} y - x^{2}) d x = 0

y = \frac{e ^{- x^{3} + c_{1}}}{3} + \frac{1}{3}

Solution steps

d y + (3 x^{2} y - x^{2}) d x = 0

Solve separable ODE:

y = \frac{e ^{- x^{3} + c_{1}}}{3} + \frac{1}{3}

y = \frac{e ^{- x^{3} + c_{1}}}{3} + \frac{1}{3}

\int cos (x + y) d x

s \to 8 + lim (f (s))

9 - x^{2}, 4 x

e^{(4 t)}

\int 9 - 3 x d x

What is the solution for dy+(3x^2y-x^2)dx=0 ?
The solution for dy+(3x^2y-x^2)dx=0 is y=(e^{-x^3+c_{1}})/3+1/3