What is the solution for (dy)/(dx)=5+e^{y-5x+1},y(0)=-1 ?

The solution for (dy)/(dx)=5+e^{y-5x+1},y(0)=-1 is y=-ln(-x+1)+5x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=5+e^{y-5x+1},y(0)=-1

\frac{d y}{d x} = 5 + e^{y - 5 x + 1}, y (0) = - 1

y = - ln (- x + 1) + 5 x - 1

Solution steps

\frac{d y}{d x} = 5 + e^{y - 5 x + 1}

Solve using substitution:

y = - ln (- x + 1) + 5 x - 1

y = - ln (- x + 1) + 5 x - 1

x \to 2 + lim (- 1)

\frac{d}{d x} (8 x + x^{2} + 7 x + 3)

e^{17 t} t^{7}

f (x) = 50 x - 5 x

y^{^{''}} - 6 y^{^{'}} + 2 y = x e^{x}

What is the solution for (dy)/(dx)=5+e^{y-5x+1},y(0)=-1 ?
The solution for (dy)/(dx)=5+e^{y-5x+1},y(0)=-1 is y=-ln(-x+1)+5x-1