What is area 6x^2,x^2+2 ?

The answer to area 6x^2,x^2+2 is -(4sqrt(2))/(3sqrt(5))+4sqrt(2/5)

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area 6x^2,x^2+2

area

6 x^{2}, x^{2} + 2

- \frac{4 2}{3 5} + 4 \frac{2}{5}

Solution steps

Apply the area formula:

\int_{- \frac{2}{5}}^{\frac{2}{5}} 6 x^{2} - (x^{2} + 2) d x

Solve

\int_{- \frac{2}{5}}^{\frac{2}{5}} 6 x^{2} - (x^{2} + 2) d x : - \frac{4 2}{3 5} + 4 \frac{2}{5}

The area is:

= - \frac{4 2}{3 5} + 4 \frac{2}{5}

n = 2 \sum \infty (\frac{1}{3})^{n}

\frac{d}{d x} (5 x^{4} - 2 x^{3} - 3 x + 2)

y^{^{''}} + 8 y^{^{'}} + 7 y = 0

\int sin (x) cos (x) 1 - sin^{4} (x) d x

\frac{\partial}{\partial x} ((3 y) \cdot (2 x)^{- 1})

What is area 6x^2,x^2+2 ?
The answer to area 6x^2,x^2+2 is -(4sqrt(2))/(3sqrt(5))+4sqrt(2/5)