What is the derivative of y=4\sqrt[5]{x} ?

The derivative of y=4\sqrt[5]{x} is 4/(5x^{4/5)}

What is the first derivative of y=4\sqrt[5]{x} ?

The first derivative of y=4\sqrt[5]{x} is 4/(5x^{4/5)}

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derivative of

\frac{4}{5 x ^{\frac{4}{5}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 4 \frac{d}{d x} (x^{\frac{1}{5}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot \frac{1}{5} x^{\frac{1}{5} - 1}

Simplify

4 \cdot \frac{1}{5} x^{\frac{1}{5} - 1} : \frac{4}{5 x ^{\frac{4}{5}}}

= \frac{4}{5 x ^{\frac{4}{5}}}

9

x \to 9 lim (9 x + ∣ x - 9 ∣)

\frac{d}{d x} (\frac{1}{e ^{x}})

t^{3} δ (t - 1)

What is the derivative of y=4\sqrt[5]{x} ?
The derivative of y=4\sqrt[5]{x} is 4/(5x^{4/5)}
What is the first derivative of y=4\sqrt[5]{x} ?
The first derivative of y=4\sqrt[5]{x} is 4/(5x^{4/5)}