What is the derivative of y=x^3-(x^2)/(16) ?

The derivative of y=x^3-(x^2)/(16) is 3x^2-x/8

What is the first derivative of y=x^3-(x^2)/(16) ?

The first derivative of y=x^3-(x^2)/(16) is 3x^2-x/8

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derivative of

y = x^{3} - \frac{x ^{2}}{16}

3 x^{2} - \frac{x}{8}

Solution steps

\frac{d}{d x} (x^{3} - \frac{x ^{2}}{16})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (\frac{x ^{2}}{16})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (\frac{x ^{2}}{16}) = \frac{x}{8}

= 3 x^{2} - \frac{x}{8}

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What is the derivative of y=x^3-(x^2)/(16) ?
The derivative of y=x^3-(x^2)/(16) is 3x^2-x/8
What is the first derivative of y=x^3-(x^2)/(16) ?
The first derivative of y=x^3-(x^2)/(16) is 3x^2-x/8