What is the derivative of y=x^4+2x^2-x ?

The derivative of y=x^4+2x^2-x is 4x^3+4x-1

What is the first derivative of y=x^4+2x^2-x ?

The first derivative of y=x^4+2x^2-x is 4x^3+4x-1

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derivative of

y = x^{4} + 2 x^{2} - x

4 x^{3} + 4 x - 1

Solution steps

\frac{d}{d x} (x^{4} + 2 x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

= 4 x^{3} + 4 x - 1

x \to 2 lim (2 x^{3})

\frac{d}{d x} (- x^{- 3})

\int - \frac{x + 1}{x} d x

4 y^{^{''}} - 4 y^{^{'}} - 3 y = 0

\frac{d y}{d x}, y^{2} = 2 x

What is the derivative of y=x^4+2x^2-x ?
The derivative of y=x^4+2x^2-x is 4x^3+4x-1
What is the first derivative of y=x^4+2x^2-x ?
The first derivative of y=x^4+2x^2-x is 4x^3+4x-1