What is the derivative of-4/(x^2) ?

The derivative of-4/(x^2) is 8/(x^3)

What is the first derivative of-4/(x^2) ?

The first derivative of-4/(x^2) is 8/(x^3)

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derivative of

- \frac{4}{x ^{2}}

\frac{8}{x ^{3}}

Solution steps

\frac{d}{d x} (- \frac{4}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 4 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 4 (- 2 x^{- 2 - 1})

Simplify

- 4 (- 2 x^{- 2 - 1}) : \frac{8}{x ^{3}}

= \frac{8}{x ^{3}}

\int \frac{1}{3 - 7 x} d x

f (x) = arcsin (x^{6})

\frac{\partial}{\partial x} (- \frac{x}{( x ^{2} + y ^{2} + 1 )})

\frac{d}{d x} (2 + ln (x))

\int \frac{361 - x ^{2}}{x} d x

What is the derivative of-4/(x^2) ?
The derivative of-4/(x^2) is 8/(x^3)
What is the first derivative of-4/(x^2) ?
The first derivative of-4/(x^2) is 8/(x^3)