What is area y=cos(x),y=sin(2x),x=0,x= pi/2 ?

The answer to area y=cos(x),y=sin(2x),x=0,x= pi/2 is 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=cos(x),y=sin(2x),x=0,x= pi/2

area

y = cos (x), y = sin (2 x), x = 0, x = \frac{π}{2}

\frac{1}{2}

Decimal Notation

0.5

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{2}} ∣ cos (x) - sin (2 x) ∣ d x

Solve

\int_{0}^{\frac{π}{2}} ∣ cos (x) - sin (2 x) ∣ d x : \frac{1}{2}

The area is:

= \frac{1}{2}

\int tan^{4} (3 x) d x

\frac{\partial}{\partial x} (ln (x yz))

f (x) = \frac{3}{4 x + 7}

\frac{d}{d x} (\frac{2 x - 5}{x + 1})

x \to 0 lim (2 x cot (4 x))

What is area y=cos(x),y=sin(2x),x=0,x= pi/2 ?
The answer to area y=cos(x),y=sin(2x),x=0,x= pi/2 is 1/2