What is (\partial)/(\partial x)(x^7+3^y+x^y) ?

The answer to (\partial)/(\partial x)(x^7+3^y+x^y) is 7x^6+yx^{y-1}

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(\partial)/(\partial x)(x^7+3^y+x^y)

\frac{\partial}{\partial x} (x^{7} + 3^{y} + x^{y})

7 x^{6} + y x^{y - 1}

Solution steps

\frac{\partial}{\partial x} (x^{7} + 3^{y} + x^{y})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{7}) + \frac{\partial}{\partial x} (3^{y}) + \frac{\partial}{\partial x} (x^{y})

\frac{\partial}{\partial x} (x^{7}) = 7 x^{6}

\frac{\partial}{\partial x} (3^{y}) = 0

\frac{\partial}{\partial x} (x^{y}) = y x^{y - 1}

= 7 x^{6} + 0 + y x^{y - 1}

Simplify

= 7 x^{6} + y x^{y - 1}

\frac{d}{d y} (- ln (y))

\int - \frac{cos ( 2 x )}{2} d x

\frac{3}{4 x ^{4}}

\int \frac{1}{w ^{2} w ^{2} - 7} d w

y^{^{''}} - 6 y^{^{'}} + 9 y = x e^{x}

What is (\partial)/(\partial x)(x^7+3^y+x^y) ?
The answer to (\partial)/(\partial x)(x^7+3^y+x^y) is 7x^6+yx^{y-1}