What is the derivative of x-3\sqrt[3]{x} ?

The derivative of x-3\sqrt[3]{x} is 1-1/(x^{2/3)}

What is the first derivative of x-3\sqrt[3]{x} ?

The first derivative of x-3\sqrt[3]{x} is 1-1/(x^{2/3)}

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1 - \frac{1}{x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d x}{d x} = 1

= 1 - \frac{1}{x ^{\frac{2}{3}}}

y^{^{''}} - 8 y^{^{'}} + 15 y = 4 e^{t}

\int \frac{x}{( 1 + x ^{2} ) ^{2}} d x

\frac{d}{d x} (lo g_{3} (4 x^{2} + 2 x))

\frac{\partial}{\partial x} (2 x + 3 e^{y} + x y)

\frac{10 s}{( s + 1 ) ( s + 6 )}

What is the derivative of x-3\sqrt[3]{x} ?
The derivative of x-3\sqrt[3]{x} is 1-1/(x^{2/3)}
What is the first derivative of x-3\sqrt[3]{x} ?
The first derivative of x-3\sqrt[3]{x} is 1-1/(x^{2/3)}