What is the limit as x approaches+0+of 1/x-1/(x^2+x) ?

The limit as x approaches+0+of 1/x-1/(x^2+x) is 1

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limit as x approaches+0+of 1/x-1/(x^2+x)

x \to + 0 + lim (\frac{1}{x} - \frac{1}{x ^{2} + x})

1

Solution steps

x \to 0 + lim (\frac{1}{x} - \frac{1}{x ^{2} + x})

Simplify

\frac{1}{x} - \frac{1}{x ^{2} + x} : \frac{1}{x + 1}

= x \to 0 + lim (\frac{1}{x + 1})

Plug in the value

x = 0

= \frac{1}{0 + 1}

Simplify

= 1

\frac{\partial}{\partial x} (e^{\frac{y}{x}} - y \cdot e^{- x})

x \to 0 lim (x^{4} sin (\frac{4}{x}))

\frac{1 + 4 s}{s ( 2 s ^{2} + 2 s + 1 )}

\frac{d}{d x} (\frac{ln ( x )}{1 + x})

y^{^{'}} - 12 x^{11} y = e^{x^{12}}

What is the limit as x approaches+0+of 1/x-1/(x^2+x) ?
The limit as x approaches+0+of 1/x-1/(x^2+x) is 1