What is the solution for ydx=2(x+y)dy ?

The solution for ydx=2(x+y)dy is y=(1+sqrt(c_{1)x+1})/(c_{1)},y=(1-sqrt(c_{1)x+1})/(c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ydx=2(x+y)dy

y d x = 2 (x + y) d y

y = \frac{1 + c _{1} x + 1}{c _{1}}, y = \frac{1 - c _{1} x + 1}{c _{1}}

Solution steps

y d x = 2 (x + y) d y

Solve exact ODE:

y = \frac{1 + c _{1} x + 1}{c _{1}}, y = \frac{1 - c _{1} x + 1}{c _{1}}

y = \frac{1 + c _{1} x + 1}{c _{1}}, y = \frac{1 - c _{1} x + 1}{c _{1}}

(x + y) d x + (x + 2 y) d y = 0, y (2) = 3

x \to 0 - lim (\frac{1}{1 + e ^{\frac{1}{x}}})

\frac{d}{d x} (2 arctan (4 x))

x \to 0 lim (x^{2} ln (x^{2}))

\int \frac{1}{( x ^{2} - 16 ) ^{\frac{3}{2}}} d x

What is the solution for ydx=2(x+y)dy ?
The solution for ydx=2(x+y)dy is y=(1+sqrt(c_{1)x+1})/(c_{1)},y=(1-sqrt(c_{1)x+1})/(c_{1)}