What is the integral of 2sin(x)-3sec(x)tan(x) ?

The integral of 2sin(x)-3sec(x)tan(x) is -2cos(x)-3sec(x)+C

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integral of 2sin(x)-3sec(x)tan(x)

\int 2 sin (x) - 3 sec (x) tan (x) d x

- 2 cos (x) - 3 sec (x) + C

Solution steps

\int 2 sin (x) - 3 sec (x) tan (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 sin (x) d x - \int 3 sec (x) tan (x) d x

\int 2 sin (x) d x = - 2 cos (x)

\int 3 sec (x) tan (x) d x = 3 sec (x)

= - 2 cos (x) - 3 sec (x)

Add a constant to the solution

= - 2 cos (x) - 3 sec (x) + C

\int \frac{t ^{5}}{( t ^{2} + 4 ) ^{2}} d t

\frac{d}{d x} (ln (arccos (x)))

2 y^{^{''}} + 5 y^{^{'}} - 18 y = 0

\frac{d x}{d t} = t^{\frac{3}{2}}, x (3) = 7

x \to - 1 lim (\frac{1 + x ^{3}}{1 + x})

What is the integral of 2sin(x)-3sec(x)tan(x) ?
The integral of 2sin(x)-3sec(x)tan(x) is -2cos(x)-3sec(x)+C