What is the integral from 1 to infinity of x^{-4/3} ?

The integral from 1 to infinity of x^{-4/3} is 3

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integral from 1 to infinity of x^{-4/3}

\int_{1}^{\infty} x^{- \frac{4}{3}} d x

3

Solution steps

\int_{1}^{\infty} x^{- \frac{4}{3}} d x

Compute the indefinite integral:

\int x^{- \frac{4}{3}} d x = - \frac{3}{x ^{\frac{1}{3}}} + C

Compute the boundaries:

\int_{1}^{\infty} x^{- \frac{4}{3}} d x = 0 - (- 3)

= 0 - (- 3)

Simplify

= 3

\frac{\partial}{\partial x} (e^{- x^{2} - 2 y^{2}})

\int 8 sec (x) (sec (x) - 4 tan (x)) d x

y^{^{''}} + 8 y^{^{'}} + 4 y = t

\frac{\partial}{\partial y} (sin (z))

4 x + 9, 144 - x, - 9, 144

What is the integral from 1 to infinity of x^{-4/3} ?
The integral from 1 to infinity of x^{-4/3} is 3