What is the derivative of 2xe^xcsc(x) ?

The derivative of 2xe^xcsc(x) is 2(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))

What is the first derivative of 2xe^xcsc(x) ?

The first derivative of 2xe^xcsc(x) is 2(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))

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derivative of

2 x e^{x} csc (x)

2 (e^{x} csc (x) + x (e^{x} csc (x) - e^{x} cot (x) csc (x)))

Solution steps

\frac{d}{d x} (2 x e^{x} csc (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x e^{x} csc (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x} csc (x)

= 2 (\frac{d x}{d x} e^{x} csc (x) + \frac{d}{d x} (e^{x} csc (x)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x} csc (x)) = e^{x} csc (x) - e^{x} cot (x) csc (x)

= 2 (1 \cdot e^{x} csc (x) + (e^{x} csc (x) - e^{x} cot (x) csc (x)) x)

Simplify

= 2 (e^{x} csc (x) + x (e^{x} csc (x) - e^{x} cot (x) csc (x)))

\int \frac{t}{2 y ^{4}} d t

\int \frac{( 7 x - 4 ) ( 3 x + 5 ) ^{2}}{x ^{2}} d x

\frac{\partial ^{2}}{\partial y ^{2}} (\frac{x}{x ^{2} + y ^{2}})

\int sin^{5} (2 x) cos^{2} (2 x) d x

f (x) = 2 x^{2} + 7

What is the derivative of 2xe^xcsc(x) ?
The derivative of 2xe^xcsc(x) is 2(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))
What is the first derivative of 2xe^xcsc(x) ?
The first derivative of 2xe^xcsc(x) is 2(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))