What is the integral from 1 to 3 of 3/x-3/(x^2) ?

The integral from 1 to 3 of 3/x-3/(x^2) is 3ln(3)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of 3/x-3/(x^2)

\int_{1}^{3} \frac{3}{x} - \frac{3}{x ^{2}} d x

3 ln (3) - 2

Decimal Notation

1.29583 \dots

Solution steps

\int_{1}^{3} \frac{3}{x} - \frac{3}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} \frac{3}{x} d x - \int_{1}^{3} \frac{3}{x ^{2}} d x

\int_{1}^{3} \frac{3}{x} d x = 3 ln (3)

\int_{1}^{3} \frac{3}{x ^{2}} d x = 2

= 3 ln (3) - 2

\int x^{3} e^{- 0.25 x} d x

\frac{d}{d x} (arcsin (2 x - 1))

f^{^{'}} (x) = 3 x

y = (x^{3} - 3 x) ln (2 x)

What is the integral from 1 to 3 of 3/x-3/(x^2) ?
The integral from 1 to 3 of 3/x-3/(x^2) is 3ln(3)-2