What is the derivative of (3x+4^6) ?

The derivative of (3x+4^6) is 18(3x+4)^5

What is the first derivative of (3x+4^6) ?

The first derivative of (3x+4^6) is 18(3x+4)^5

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\frac{d}{d x} ((3 x + 4)^{6})

18 (3 x + 4)^{5}

Solution steps

\frac{d}{d x} ((3 x + 4)^{6})

Apply the chain rule:

6 (3 x + 4)^{5} \frac{d}{d x} (3 x + 4)

= 6 (3 x + 4)^{5} \frac{d}{d x} (3 x + 4)

\frac{d}{d x} (3 x + 4) = 3

= 6 (3 x + 4)^{5} \cdot 3

Simplify

= 18 (3 x + 4)^{5}

\frac{d}{d x} (- e^{7 x})

\frac{d}{d x} (5 cos (π x))

\int 2 x e^{5 x} d x

n = 1 \sum \infty \frac{1}{4 + e ^{- n}}

\frac{d}{d x} (\frac{1}{e ^{3 x}})

What is the derivative of (3x+4^6) ?
The derivative of (3x+4^6) is 18(3x+4)^5
What is the first derivative of (3x+4^6) ?
The first derivative of (3x+4^6) is 18(3x+4)^5