What is the integral of 1/(cos^2(2x)) ?

The integral of 1/(cos^2(2x)) is 1/2 tan(2x)+C

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integral of 1/(cos^2(2x))

\int \frac{1}{cos ^{2} ( 2 x )} d x

\frac{1}{2} tan (2 x) + C

Solution steps

\int \frac{1}{cos ^{2} ( 2 x )} d x

Rewrite using trig identities

= \int sec^{2} (2 x) d x

Apply u-substitution

: \int sec^{2} (u) \frac{1}{2} d u

= \int sec^{2} (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= \frac{1}{2} tan (u)

Substitute back

u = 2 x

= \frac{1}{2} tan (2 x)

Add a constant to the solution

= \frac{1}{2} tan (2 x) + C

y^{^{''}} + y^{^{'}} - 2 y = e^{- x}

\frac{\partial}{\partial x} (2^{\frac{1}{x}})

(3, 5), (8, 7)

\int \frac{3 x ^{2} - 6 x ^{2} + x}{x ^{3}} d x

What is the integral of 1/(cos^2(2x)) ?
The integral of 1/(cos^2(2x)) is 1/2 tan(2x)+C