What is the solution for (2x+3)+(2y-2)(dy)/(dx)=0 ?

The solution for (2x+3)+(2y-2)(dy)/(dx)=0 is y=1+sqrt(-x^2-3x+c_{1)+1},y=1-sqrt(-x^2-3x+c_{1)+1}

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(2x+3)+(2y-2)(dy)/(dx)=0

(2 x + 3) + (2 y - 2) \frac{d y}{d x} = 0

y = 1 + - x^{2} - 3 x + c_{1} + 1, y = 1 - - x^{2} - 3 x + c_{1} + 1

Solution steps

(2 x + 3) + (2 y - 2) \frac{d y}{d x} = 0

Solve separable ODE:

y = 1 + - x^{2} - 3 x + c_{1} + 1, y = 1 - - x^{2} - 3 x + c_{1} + 1

y = 1 + - x^{2} - 3 x + c_{1} + 1, y = 1 - - x^{2} - 3 x + c_{1} + 1

3 x^{2} + 2 x y + 3 y^{2} + (x^{2} + 6 x y) y^{^{'}} = 0

\frac{d}{d x} (4 x^{4} e^{- x})

\int \frac{y - 1}{y + 1} d y

\frac{d}{d x} (3 x ln (4 x) - 3 x)

\frac{\partial}{\partial x} (6 ze x yz)

What is the solution for (2x+3)+(2y-2)(dy)/(dx)=0 ?
The solution for (2x+3)+(2y-2)(dy)/(dx)=0 is y=1+sqrt(-x^2-3x+c_{1)+1},y=1-sqrt(-x^2-3x+c_{1)+1}