What is the derivative of 3x^{2/3}-6x^{1/3}+x^{-1/3} ?

The derivative of 3x^{2/3}-6x^{1/3}+x^{-1/3} is 2/(x^{1/3)}-2/(x^{2/3)}-1/(3x^{4/3)}

What is the first derivative of 3x^{2/3}-6x^{1/3}+x^{-1/3} ?

The first derivative of 3x^{2/3}-6x^{1/3}+x^{-1/3} is 2/(x^{1/3)}-2/(x^{2/3)}-1/(3x^{4/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (3 x^{\frac{2}{3}} - 6 x^{\frac{1}{3}} + x^{- \frac{1}{3}})

\frac{2}{x ^{\frac{1}{3}}} - \frac{2}{x ^{\frac{2}{3}}} - \frac{1}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (3 x^{\frac{2}{3}} - 6 x^{\frac{1}{3}} + x^{- \frac{1}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{\frac{2}{3}}) - \frac{d}{d x} (6 x^{\frac{1}{3}}) + \frac{d}{d x} (x^{- \frac{1}{3}})

\frac{d}{d x} (3 x^{\frac{2}{3}}) = \frac{2}{x ^{\frac{1}{3}}}

\frac{d}{d x} (6 x^{\frac{1}{3}}) = \frac{2}{x ^{\frac{2}{3}}}

\frac{d}{d x} (x^{- \frac{1}{3}}) = - \frac{1}{3 x ^{\frac{4}{3}}}

= \frac{2}{x ^{\frac{1}{3}}} - \frac{2}{x ^{\frac{2}{3}}} - \frac{1}{3 x ^{\frac{4}{3}}}

\frac{d}{d x} (\frac{1}{2} x sin (x))

\int 9 t sec^{2} (2 t) d t

\int 7 sin^{2} (x) cos^{3} (x) d x

n = 0 \sum \infty \frac{8 ^{n}}{n !}

e^{2 t} sin (t)

What is the derivative of 3x^{2/3}-6x^{1/3}+x^{-1/3} ?
The derivative of 3x^{2/3}-6x^{1/3}+x^{-1/3} is 2/(x^{1/3)}-2/(x^{2/3)}-1/(3x^{4/3)}
What is the first derivative of 3x^{2/3}-6x^{1/3}+x^{-1/3} ?
The first derivative of 3x^{2/3}-6x^{1/3}+x^{-1/3} is 2/(x^{1/3)}-2/(x^{2/3)}-1/(3x^{4/3)}