What is implicit (dy)/(dx),y= 3/x ?

The answer to implicit (dy)/(dx),y= 3/x is (dy)/(dx)=-3/(x^2)

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implicit (dy)/(dx),y= 3/x

implicit derivative

\frac{d y}{d x}, y = \frac{3}{x}

\frac{d y}{d x} = - \frac{3}{x ^{2}}

Solution steps

y = \frac{3}{x}

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = - \frac{3}{x ^{2}}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{3}{x ^{2}}

\frac{d y}{d x} = - \frac{3}{x ^{2}}

x - y cos (\frac{y}{x}) d x + x cos (\frac{y}{x}) d y = 0

\frac{d}{d x} (\frac{x ^{2} - 4}{x - 3})

\frac{5}{x ^{2}}, at x = 1

\frac{t ^{4}}{24}

\int \frac{1}{6 x lo g _{2} ( x )} d x

What is implicit (dy)/(dx),y= 3/x ?
The answer to implicit (dy)/(dx),y= 3/x is (dy)/(dx)=-3/(x^2)