What is the solution for (dy)/(dx)-9/x y=(y^3)/(x^{13)},y(1)=1 ?

The solution for (dy)/(dx)-9/x y=(y^3)/(x^{13)},y(1)=1 is y=(sqrt(3)x^9)/(sqrt(-x^6+4))

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(dy)/(dx)-9/x y=(y^3)/(x^{13)},y(1)=1

\frac{d y}{d x} - \frac{9}{x} y = \frac{y ^{3}}{x ^{13}}, y (1) = 1

y = \frac{3 x ^{9}}{- x ^{6} + 4}

Solution steps

\frac{d y}{d x} - \frac{9}{x} y = \frac{y ^{3}}{x ^{13}}

Solve Bernoulli ODE:

y = \frac{3 x ^{9}}{- x ^{6} + 4}

y = \frac{3 x ^{9}}{- x ^{6} + 4}

\frac{\partial}{\partial x} (r^{2} + s^{2})

\frac{\partial}{\partial x} (e^{3 x} d y)

\frac{\partial}{\partial x} (x^{2} + 6 x y + y^{2})

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0, y (0) = 9

\frac{\partial}{\partial y} (2 x^{2} + 4 y^{2} + \frac{1}{2})

What is the solution for (dy)/(dx)-9/x y=(y^3)/(x^{13)},y(1)=1 ?
The solution for (dy)/(dx)-9/x y=(y^3)/(x^{13)},y(1)=1 is y=(sqrt(3)x^9)/(sqrt(-x^6+4))