What is the derivative of (4x+2/((3-2x)^3)) ?

The derivative of (4x+2/((3-2x)^3)) is (8(2x+3))/((3-2x)^4)

What is the first derivative of (4x+2/((3-2x)^3)) ?

The first derivative of (4x+2/((3-2x)^3)) is (8(2x+3))/((3-2x)^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{4 x + 2}{( 3 - 2 x ) ^{3}})

\frac{8 ( 2 x + 3 )}{( 3 - 2 x ) ^{4}}

Solution steps

\frac{d}{d x} (\frac{4 x + 2}{( 3 - 2 x ) ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x + 2 ) ( 3 - 2 x ) ^{3} - \frac{d}{d x} ( ( 3 - 2 x ) ^{3} ) ( 4 x + 2 )}{( ( 3 - 2 x ) ^{3} ) ^{2}}

\frac{d}{d x} (4 x + 2) = 4

\frac{d}{d x} ((3 - 2 x)^{3}) = - 6 (3 - 2 x)^{2}

= \frac{4 ( 3 - 2 x ) ^{3} - ( - 6 ( 3 - 2 x ) ^{2} ) ( 4 x + 2 )}{( ( 3 - 2 x ) ^{3} ) ^{2}}

Simplify

\frac{4 ( 3 - 2 x ) ^{3} - ( - 6 ( 3 - 2 x ) ^{2} ) ( 4 x + 2 )}{( ( 3 - 2 x ) ^{3} ) ^{2}} : \frac{8 ( 2 x + 3 )}{( 3 - 2 x ) ^{4}}

= \frac{8 ( 2 x + 3 )}{( 3 - 2 x ) ^{4}}

\frac{\partial}{\partial x} (x e^{14 x y})

y^{^{'}} = 3 - \frac{3 x}{10000}

\int t^{2} e^{2 t} d t

\int (2 x + 4) e^{2 x + 4} d x

\frac{d}{d x} ([x + (x + sin^{2} (x))^{6}]^{3})

What is the derivative of (4x+2/((3-2x)^3)) ?
The derivative of (4x+2/((3-2x)^3)) is (8(2x+3))/((3-2x)^4)
What is the first derivative of (4x+2/((3-2x)^3)) ?
The first derivative of (4x+2/((3-2x)^3)) is (8(2x+3))/((3-2x)^4)