What is the integral of-2/(x^2+1) ?

The integral of-2/(x^2+1) is -2arctan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-2/(x^2+1)

\int - \frac{2}{x ^{2} + 1} d x

- 2 arctan (x) + C

Solution steps

\int - \frac{2}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= - 2 arctan (x)

Add a constant to the solution

= - 2 arctan (x) + C

\frac{\partial}{\partial x} (5 e^{x y + 4})

y^{^{''}} + 25 y = 2 tan (5 x)

\frac{2 s + 5}{s ^{2} + 5 s + 6}

\frac{d}{d x} (arctan (g (x)) x)

x, x = 1