What is the integral of-x^{1/3} ?

The integral of-x^{1/3} is -3/4 x^{4/3}+C

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integral of-x^{1/3}

\int - x^{\frac{1}{3}} d x

- \frac{3}{4} x^{\frac{4}{3}} + C

Solution steps

\int - x^{\frac{1}{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int x^{\frac{1}{3}} d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= - \frac{3}{4} x^{\frac{4}{3}}

Add a constant to the solution

= - \frac{3}{4} x^{\frac{4}{3}} + C

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