What is the tangent of-3x^2+7x ?

The tangent of-3x^2+7x is y=(-6a_{0}+7)x+3a_{0}^2

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tangent of-3x^2+7x

tangent of

- 3 x^{2} + 7 x

y = (- 6 a_{0} + 7) x + 3 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 3 a_{0}^{2} + 7 a_{0})

Find the slope of

y = - 3 x^{2} + 7 x : \frac{d y}{d x} = - 6 x + 7

Compute the slope of

y = - 3 x^{2} + 7 x

x = a_{0} : m = - 6 a_{0} + 7

Find the line with slope m=

- 6 a_{0} + 7

and passing through

(a_{0}, - 3 a_{0}^{2} + 7 a_{0}) : y = (- 6 a_{0} + 7) x + 3 a_{0}^{2}

y = (- 6 a_{0} + 7) x + 3 a_{0}^{2}

\int tan (x) sec^{5} (x) d x

\frac{\partial}{\partial x} (sin (n x) e^{- n y})

x^{8} e^{x}

\int x + 4 d x

\frac{d}{d x} ((1 + 4 x^{2}) (x - x^{2}))

What is the tangent of-3x^2+7x ?
The tangent of-3x^2+7x is y=(-6a_{0}+7)x+3a_{0}^2