What is the tangent of 4(x-1/x)^2,\at x=2 ?

The tangent of 4(x-1/x)^2,\at x=2 is y=15x-21

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tangent of 4(x-1/x)^2,\at x=2

tangent of

4 (x - \frac{1}{x})^{2}, at x = 2

y = 15 x - 21

Solution steps

Find the tangent point:

(2, 9)

Find the slope of

y = 4 (x - \frac{1}{x})^{2} : \frac{d y}{d x} = 4 (2 x - \frac{2}{x ^{3}})

Compute the slope of

y = 4 (x - \frac{1}{x})^{2}

x = 2 : m = 15

Find the line with slope m=

15

and passing through

(2, 9) : y = 15 x - 21

y = 15 x - 21

f (x) = 4 x^{7} - 5 cos (x)

\int e^{x} x d x

n = 1 \sum \infty \frac{n !}{1 8 ^{n}}

ln (sin (11 x))

x \to - 2 lim (x^{2} + 3 x)

What is the tangent of 4(x-1/x)^2,\at x=2 ?
The tangent of 4(x-1/x)^2,\at x=2 is y=15x-21