What is the derivative of (t^2-2)^2 ?

The derivative of (t^2-2)^2 is 4t(t^2-2)

What is the first derivative of (t^2-2)^2 ?

The first derivative of (t^2-2)^2 is 4t(t^2-2)

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derivative of

(t^{2} - 2)^{2}

4 t (t^{2} - 2)

Solution steps

\frac{d}{d t} ((t^{2} - 2)^{2})

Apply the chain rule:

2 (t^{2} - 2) \frac{d}{d t} (t^{2} - 2)

= 2 (t^{2} - 2) \frac{d}{d t} (t^{2} - 2)

\frac{d}{d t} (t^{2} - 2) = 2 t

= 2 (t^{2} - 2) \cdot 2 t

Simplify

= 4 t (t^{2} - 2)

25 y^{^{''}} - 20 y^{^{'}} + 4 y = 0

\int cos (w x) d x

x \frac{d y}{d x} = - 1.5 y

x \to + 0 lim (4 - x)

\frac{\partial}{\partial x} (x v - w)

What is the derivative of (t^2-2)^2 ?
The derivative of (t^2-2)^2 is 4t(t^2-2)
What is the first derivative of (t^2-2)^2 ?
The first derivative of (t^2-2)^2 is 4t(t^2-2)