What is the integral of x\sqrt[3]{2x+3} ?

The integral of x\sqrt[3]{2x+3} is 1/4 (3/7 (2x+3)^{7/3}-9/4 (2x+3)^{4/3})+C

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integral of x\sqrt[3]{2x+3}

\frac{1}{4} (\frac{3}{7} (2 x + 3)^{\frac{7}{3}} - \frac{9}{4} (2 x + 3)^{\frac{4}{3}}) + C

Solution steps

Apply u-substitution

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int u^{\frac{4}{3}} d u = \frac{3}{7} u^{\frac{7}{3}}

= \frac{1}{4} (\frac{3}{7} u^{\frac{7}{3}} - \frac{9}{4} u^{\frac{4}{3}})

Substitute back

u = 2 x + 3

= \frac{1}{4} (\frac{3}{7} (2 x + 3)^{\frac{7}{3}} - \frac{9}{4} (2 x + 3)^{\frac{4}{3}})

Add a constant to the solution

= \frac{1}{4} (\frac{3}{7} (2 x + 3)^{\frac{7}{3}} - \frac{9}{4} (2 x + 3)^{\frac{4}{3}}) + C

x \to + 1 lim (3 x^{3} - 4 x^{2} + x + 9)

y = e^{\frac{x}{2}}

\int 2 x y e^{x + y} d x

y^{^{'}} = - y t + 0.1 y^{^{'}} t + 4

What is the integral of x\sqrt[3]{2x+3} ?
The integral of x\sqrt[3]{2x+3} is 1/4 (3/7 (2x+3)^{7/3}-9/4 (2x+3)^{4/3})+C