What is (\partial)/(\partial x)(ysin(2x)) ?

The answer to (\partial)/(\partial x)(ysin(2x)) is ycos(2x)*2

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(\partial)/(\partial x)(ysin(2x))

\frac{\partial}{\partial x} (y sin (2 x))

y cos (2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (y sin (2 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= y cos (2 x) \cdot 2

x \to 0 + lim (\frac{1}{ln ( x )})

x y y^{^{'}} = 2 y^{2} + 4 x^{2}

x \to x lim (tan (x))

\frac{4}{( s - 4 ) ^{3}}

\frac{\partial}{\partial x} (3 cos (2 x))

What is (\partial)/(\partial x)(ysin(2x)) ?
The answer to (\partial)/(\partial x)(ysin(2x)) is ycos(2x)*2