What is the derivative of (x-4^2-5) ?

The derivative of (x-4^2-5) is 2x-8

What is the first derivative of (x-4^2-5) ?

The first derivative of (x-4^2-5) is 2x-8

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\frac{d}{d x} ((x - 4)^{2} - 5)

2 x - 8

Solution steps

\frac{d}{d x} ((x - 4)^{2} - 5)

Simplify

(x - 4)^{2} - 5 : x^{2} - 8 x + 11

= \frac{d}{d x} (x^{2} - 8 x + 11)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (11)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (11) = 0

= 2 x - 8 + 0

Simplify

= 2 x - 8

n = 0 \sum \infty n e^{- n^{2}}

f (x) = (1 + 3 x^{2}) (x - x^{2})

y^{^{'}} + 2 y = t e^{- 2 t}, y (1) = 0

\int [(3 - x^{2})^{3}] d x

\int \frac{- 3}{( x - 2 ) ( x ^{2} + 4 )} d x

What is the derivative of (x-4^2-5) ?
The derivative of (x-4^2-5) is 2x-8
What is the first derivative of (x-4^2-5) ?
The first derivative of (x-4^2-5) is 2x-8