What is the derivative of 3/(x^3+x^{-4}) ?

The derivative of 3/(x^3+x^{-4}) is -9/(x^4)-4/(x^5)

What is the first derivative of 3/(x^3+x^{-4}) ?

The first derivative of 3/(x^3+x^{-4}) is -9/(x^4)-4/(x^5)

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\frac{d}{d x} (\frac{3}{x ^{3}} + x^{- 4})

- \frac{9}{x ^{4}} - \frac{4}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{3}} + x^{- 4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3}{x ^{3}}) + \frac{d}{d x} (x^{- 4})

\frac{d}{d x} (\frac{3}{x ^{3}}) = - \frac{9}{x ^{4}}

\frac{d}{d x} (x^{- 4}) = - \frac{4}{x ^{5}}

= - \frac{9}{x ^{4}} - \frac{4}{x ^{5}}

\int \frac{x ^{3}}{1 - 9 x ^{2}} d x

y = \frac{x + 7}{5 x ^{2} e ^{x}}

\int (\frac{4}{x} + e^{2 x}) d x

\int sec (x) sec^{2} (x) d x

\int x cos (π \cdot x) d x

What is the derivative of 3/(x^3+x^{-4}) ?
The derivative of 3/(x^3+x^{-4}) is -9/(x^4)-4/(x^5)
What is the first derivative of 3/(x^3+x^{-4}) ?
The first derivative of 3/(x^3+x^{-4}) is -9/(x^4)-4/(x^5)