What is the derivative of (2x^9-5x+sqrt(x)/(x^4)) ?

The derivative of (2x^9-5x+sqrt(x)/(x^4)) is (20x^9+30x-7sqrt(x))/(2x^5)

What is the first derivative of (2x^9-5x+sqrt(x)/(x^4)) ?

The first derivative of (2x^9-5x+sqrt(x)/(x^4)) is (20x^9+30x-7sqrt(x))/(2x^5)

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\frac{d}{d x} (\frac{2 x ^{9} - 5 x + x}{x ^{4}})

\frac{20 x ^{9} + 30 x - 7 x}{2 x ^{5}}

Solution steps

\frac{d}{d x} (\frac{2 x ^{9} - 5 x + x}{x ^{4}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x ^{9} - 5 x + x ) x ^{4} - \frac{d}{d x} ( x ^{4} ) ( 2 x ^{9} - 5 x + x )}{( x ^{4} ) ^{2}}

\frac{d}{d x} (2 x^{9} - 5 x + x) = 18 x^{8} - 5 + \frac{1}{2 x}

\frac{d}{d x} (x^{4}) = 4 x^{3}

= \frac{( 18 x ^{8} - 5 + \frac{1}{2 x} ) x ^{4} - 4 x ^{3} ( 2 x ^{9} - 5 x + x )}{( x ^{4} ) ^{2}}

Simplify

\frac{( 18 x ^{8} - 5 + \frac{1}{2 x} ) x ^{4} - 4 x ^{3} ( 2 x ^{9} - 5 x + x )}{( x ^{4} ) ^{2}} : \frac{20 x ^{9} + 30 x - 7 x}{2 x ^{5}}

= \frac{20 x ^{9} + 30 x - 7 x}{2 x ^{5}}

\int_{0}^{r} 0 d r

\int \frac{5}{( x - 2 ) ( x ^{2} + 4 )} d x

\int x^{2} I n d x

lo g_{a} (x)

n = 3 \sum \infty \frac{2}{n ^{2} - 2 n}

What is the derivative of (2x^9-5x+sqrt(x)/(x^4)) ?
The derivative of (2x^9-5x+sqrt(x)/(x^4)) is (20x^9+30x-7sqrt(x))/(2x^5)
What is the first derivative of (2x^9-5x+sqrt(x)/(x^4)) ?
The first derivative of (2x^9-5x+sqrt(x)/(x^4)) is (20x^9+30x-7sqrt(x))/(2x^5)