What is the solution for y^'-7/x y=(y^4)/(x^5) ?

The solution for y^'-7/x y=(y^4)/(x^5) is y=(\sqrt[3]{17}x^7)/(\sqrt[3]{-3x^{17)+c_{1}}}

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y^'-7/x y=(y^4)/(x^5)

y^{^{'}} - \frac{7}{x} y = \frac{y ^{4}}{x ^{5}}

Solution steps

y^{'} (x) - \frac{7}{x} y = \frac{y ^{4}}{x ^{5}}

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What is the solution for y^'-7/x y=(y^4)/(x^5) ?
The solution for y^'-7/x y=(y^4)/(x^5) is y=(\sqrt[3]{17}x^7)/(\sqrt[3]{-3x^{17)+c_{1}}}