What is the d/(dt)(2/(2-cos(pit))) ?

The d/(dt)(2/(2-cos(pit))) is -(2pisin(pit))/((2-cos(pit))^2)

What is the first d/(dt)(2/(2-cos(pit))) ?

The first d/(dt)(2/(2-cos(pit))) is -(2pisin(pit))/((2-cos(pit))^2)

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\frac{d}{d t} (\frac{2}{2 - cos ( π t )})

- \frac{2 π sin ( π t )}{( 2 - cos ( π t ) ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{2}{2 - cos ( π t )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (\frac{1}{2 - cos ( π t )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d t} ((2 - cos (π t))^{- 1})

Apply the chain rule:

- \frac{1}{( 2 - cos ( π t ) ) ^{2}} \frac{d}{d t} (2 - cos (π t))

= - \frac{1}{( 2 - cos ( π t ) ) ^{2}} \frac{d}{d t} (2 - cos (π t))

\frac{d}{d t} (2 - cos (π t)) = π sin (π t)

= 2 (- \frac{1}{( 2 - cos ( π t ) ) ^{2}} π sin (π t))

Simplify

2 (- \frac{1}{( 2 - cos ( π t ) ) ^{2}} π sin (π t)) : - \frac{2 π sin ( π t )}{( 2 - cos ( π t ) ) ^{2}}

= - \frac{2 π sin ( π t )}{( 2 - cos ( π t ) ) ^{2}}

\frac{d}{d x} (2 e^{c o s (\frac{x}{2})})

\frac{( x ^{2} - 3 x )}{x + 1}

\int \frac{2 x + 1}{x ^{2} - x - 6} d x

\int 4 sech (x) tanh (x) d x

x \to 0 lim (2 x^{3})

What is the d/(dt)(2/(2-cos(pit))) ?
The d/(dt)(2/(2-cos(pit))) is -(2pisin(pit))/((2-cos(pit))^2)
What is the first d/(dt)(2/(2-cos(pit))) ?
The first d/(dt)(2/(2-cos(pit))) is -(2pisin(pit))/((2-cos(pit))^2)