What is the integral from 0 to 0.5 of (300x) ?

The integral from 0 to 0.5 of (300x) is 37.5

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integral from 0 to 0.5 of (300x)

\int_{0}^{0.5} (300 x) d x

37.5

Solution steps

\int_{0}^{0.5} 300 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 300 \cdot \int_{0}^{0.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.5}

= 300 [\frac{x ^{2}}{2}]_{0}^{0.5}

Simplify

= 300 [0.5 x^{2}]_{0}^{0.5}

Compute the boundaries:

0.125

= 300 \cdot 0.125

Simplify

= 37.5

y^{^{''}} = 4 t^{3} + t

y = (x - 5) x (x + 5), y = 5 - x

\int_{0}^{0.6} 150 x d x

\frac{( 1 - e ^{- s} )}{s}

\frac{d}{d x} (\frac{e ^{x}}{cos ( x )})

What is the integral from 0 to 0.5 of (300x) ?
The integral from 0 to 0.5 of (300x) is 37.5