What is the integral from 2 to 4 of ((x+y))/(55) ?

The integral from 2 to 4 of ((x+y))/(55) is 1/55 (2x+6)

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integral from 2 to 4 of ((x+y))/(55)

\int_{2}^{4} \frac{( x + y )}{55} d y

\frac{1}{55} (2 x + 6)

Solution steps

\int_{2}^{4} \frac{x + y}{55} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{55} \cdot \int_{2}^{4} x + y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{55} (\int_{2}^{4} x d y + \int_{2}^{4} y d y)

\int_{2}^{4} x d y = 2 x

\int_{2}^{4} y d y = 6

= \frac{1}{55} (2 x + 6)

f (x) = 12 x + x

\frac{d}{d x} (sin^{2} (2 x) cos^{3} (3 x))

x \to \infty lim ((4^{x} + 4^{x})^{\frac{1}{2 x}})

\int \frac{x + 16}{x ^{2} + 2 x - 8} d x

x \to 0 lim (x^{6} cos (\frac{4}{x}))

What is the integral from 2 to 4 of ((x+y))/(55) ?
The integral from 2 to 4 of ((x+y))/(55) is 1/55 (2x+6)