What is the solution for dx-2xydy=0 ?

The solution for dx-2xydy=0 is y=sqrt(ln(x)+c_{1)},y=-sqrt(ln(x)+c_{1)}

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dx-2xydy=0

d x - 2 x y d y = 0

y = ln (x) + c_{1}, y = - ln (x) + c_{1}

Solution steps

d x - 2 x y d y = 0

Solve separable ODE:

y = ln (x) + c_{1}, y = - ln (x) + c_{1}

y = ln (x) + c_{1}, y = - ln (x) + c_{1}

\frac{d}{d x} (\frac{( x - 1 ) ( x ^{2} + x + 1 )}{x ^{3}})

f (x) = 3 - 2 x + 4 x^{3}, at x = - 1

\int \frac{1}{e ^{\frac{x}{3}} + e ^{\frac{x}{6}}} d x

\frac{d}{d x} (7 e^{8 x})

f (x) = 25 - x^{2}

What is the solution for dx-2xydy=0 ?
The solution for dx-2xydy=0 is y=sqrt(ln(x)+c_{1)},y=-sqrt(ln(x)+c_{1)}