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Popular >

area y=x^2,y=-x^2+4x

Solution

area

y = x^{2}, y = - x^{2} + 4 x

Solution

\frac{8}{3}

+1

Decimal Notation

2.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x^{2} - (- x^{2} + 4 x) d x

Solve

\int_{0}^{2} x^{2} - (- x^{2} + 4 x) d x : \frac{8}{3}

The area is:

= \frac{8}{3}

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\frac{\partial}{\partial x} (\frac{3 x + 2 y}{y ^{2} + 5 x ^{2}})

integral of 3+4x

\int 3 + 4 x d x

integral of 1/(x^4sqrt(4-x^2))

\int \frac{1}{x ^{4} 4 - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is area y=x^2,y=-x^2+4x ?
The answer to area y=x^2,y=-x^2+4x is 8/3