What is the tangent of f(x)=(-9x^2)/2+7x+2 ?

The tangent of f(x)=(-9x^2)/2+7x+2 is y=(-9a_{0}+7)x+9a_{0}^2-(9a_{0}^2)/2+2

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tangent of f(x)=(-9x^2)/2+7x+2

tangent of

f (x) = \frac{- 9 x ^{2}}{2} + 7 x + 2

y = (- 9 a_{0} + 7) x + 9 a_{0}^{2} - \frac{9 a _{0}^{2}}{2} + 2

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - \frac{9 a _{0}^{2}}{2} + 7 a_{0} + 2)

Find the slope of

f (x) = \frac{- 9 x ^{2}}{2} + 7 x + 2 : \frac{df ( x )}{d x} = - 9 x + 7

Compute the slope of

f (x) = \frac{- 9 x ^{2}}{2} + 7 x + 2

x = a_{0} : m = - 9 a_{0} + 7

Find the line with slope m=

- 9 a_{0} + 7

and passing through

(a_{0}, - \frac{9 a _{0}^{2}}{2} + 7 a_{0} + 2) : y = (- 9 a_{0} + 7) x + 9 a_{0}^{2} - \frac{9 a _{0}^{2}}{2} + 2

y = (- 9 a_{0} + 7) x + 9 a_{0}^{2} - \frac{9 a _{0}^{2}}{2} + 2

\frac{\partial}{\partial y} (arctan (x^{4} y^{3}))

5 (t - 1)

\frac{d}{d x} (\frac{A}{B + C e ^{x}})

\int e^{a x} d x

f (x) = \frac{1 - x ^{2}}{2 x + 1}

What is the tangent of f(x)=(-9x^2)/2+7x+2 ?
The tangent of f(x)=(-9x^2)/2+7x+2 is y=(-9a_{0}+7)x+9a_{0}^2-(9a_{0}^2)/2+2