What is the integral from-1 to 2 of (x^3-x+2) ?

The integral from-1 to 2 of (x^3-x+2) is 33/4

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integral from-1 to 2 of (x^3-x+2)

\int_{- 1}^{2} (x^{3} - x + 2) d x

\frac{33}{4}

Decimal Notation

8.25

Solution steps

\int_{- 1}^{2} x^{3} - x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{3} d x - \int_{- 1}^{2} x d x + \int_{- 1}^{2} 2 d x

\int_{- 1}^{2} x^{3} d x = \frac{15}{4}

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 2 d x = 6

= \frac{15}{4} - \frac{3}{2} + 6

Simplify

\frac{15}{4} - \frac{3}{2} + 6 : \frac{33}{4}

= \frac{33}{4}

\frac{d}{d x} ((10 - 5 x)^{4})

f (x) = (cot (x))^{4}

g (u) = (\frac{u ^{3} - 1}{u ^{3} + 1})^{8}

\frac{\partial}{\partial v} (uv)

18 y^{^{'}} = y (y^{2} - 9)

What is the integral from-1 to 2 of (x^3-x+2) ?
The integral from-1 to 2 of (x^3-x+2) is 33/4