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Popular >

area x^2-2x+3,x=-2,x=1

Solution

area

x^{2} - 2 x + 3, x = - 2, x = 1

Solution

15

Solution steps

Apply the area formula:

\int_{- 2}^{1} x^{2} - 2 x + 3 d x

Solve

\int_{- 2}^{1} x^{2} - 2 x + 3 d x : 15

The area is:

= 15

Popular Examples

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\frac{d}{d x} ((2 x^{2} - 6)^{- 10})

y^{''}-8y^'+16y=t-2e^{4t}

y^{^{''}} - 8 y^{^{'}} + 16 y = t - 2 e^{4 t}

integral of (x^3-1)^2

\int (x^{3} - 1)^{2} d x

(dy)/(dx)=cos(x)*e^{y+sin(x)}

\frac{d y}{d x} = cos (x) \cdot e^{y + s i n (x)}

integral from 0 to 1 of (31)/(4y-1)

\int_{0}^{1} \frac{31}{4 y - 1} d y

Frequently Asked Questions (FAQ)

What is area x^2-2x+3,x=-2,x=1 ?
The answer to area x^2-2x+3,x=-2,x=1 is 15