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Popular >

x^2-2xy+xy^'=0

Solution

x^{2} - 2 x y + x y^{^{'}} = 0

Solution

y = \frac{2 x + 1}{4} + c_{1} e^{2 x}

Solution steps

x^{2} - 2 x y + x y^{'} (x) = 0

Solve linear ODE:

y = \frac{2 x + 1}{4} + c_{1} e^{2 x}

y = \frac{2 x + 1}{4} + c_{1} e^{2 x}

Popular Examples

integral of (x+4)/(x^2+5x+4)

\int \frac{x + 4}{x ^{2} + 5 x + 4} d x

limit as x approaches 3+of ln(x^2-9)

x \to 3 + lim (ln (x^{2} - 9))

(-1/((1+x)^2))^'

(- \frac{1}{( 1 + x ) ^{2}})^{^{'}}

integral of (a+bx^2)/(sqrt(3ax+bx^3))

\int \frac{a + b x ^{2}}{3 a x + b x ^{3}} d x

derivative of arccos(3x)

\frac{d}{d x} (arccos (3 x))

Frequently Asked Questions (FAQ)

What is the solution for x^2-2xy+xy^'=0 ?
The solution for x^2-2xy+xy^'=0 is y=(2x+1)/4+c_{1}e^{2x}